WebDec 5, 2024 · Q19 In an AP if Sn = n ( 4n + 1 ) , then find the AP. If s n = 4 4n + 1, find the AP SARAL INSTITUTE 6.85K subscribers Subscribe 504 views 3 months ago CLASS 10 CBSE... WebMar 31, 2024 · Best answer Sn=5n2+4n S1=5 (1)^2+4 (1) =5+4 =9 Therefore a1=s1=9 S2=5 (2)^2+4 (2) =5 (4)+8 =28 a2=S2-S1 a2=28-9=19 D=10 A8=a+7d =9+7 (10) =9+70 =79 0 votes answered Apr 1, 2024 by SuhaniKumari (30.9k points) Sum of n natural numbers Sn = 5n2 + 4n Sum of (n - 1) natural numbers 8th term = t8 = 10 x 8 - 1 = 80 - 1 = 79 ← Prev Question …
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WebThe n th term of an AP can be obtained by a n = a + (n − 1)d; The sum of an AP can be obtained by s n = n/2 [2a + (n − 1) d] The graph of an AP is a straight line with the slope as … WebMar 31, 2024 · S n = n (4n + 1) Formula: a = first term d = common difference Calculation: S 1 = 1 (4 × 1 + 1) ⇒ S 1 = 4 + 1 = 5 S 2 = 2 (4 × 2 + 1) ⇒ S 2 = 2 × 9 = 18 Second term = S 2 – …
WebSep 20, 2024 · Sn =n ( 4n + 1 ) = 4n^2 + n we know that, Tn = Sn - S (n-1) =4n^2+n -4 (n-1)^2 - (n-1) =4 (n^2-n^2+2n-1)+ (n-n+1) =8n - 4 + 1 = 8n -3 hence , Tn = 8n -3 T1 =8 (1)-3 =5 T2= 8 (2)-3 =13 so, AP is 5, 13 , 21 and so on Find Math textbook solutions? Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 NCERT Class 9 Mathematics 619 solutions WebMay 5, 2024 · 1 answer If an AP is Sn = n (4n+1), then find the AP asked May 5, 2024 in Class X Maths by kabita (13.8k points) class-10 0 votes 1 answer Find the common difference of the AP 4,9,14,… If the first term changes to 6 and the common difference remains the same then write the new AP. asked Jan 20, 2024 in Class X Maths by priya …
WebIn the given AP, the first term is a = 7 and the common difference is d = 4. Let us assume that 301 is the n th term of AP. Then: T n = a + (n - 1)d 301 = 7 + (n - 1) 4 301 = 7 + 4n - 4 301 = 4n + 3 298 = 4n n = 74.5 But 'n' must be an integer. Hence 301 cannot be a term of the given AP. Answer: 301 cannot be a term of the given AP. WebFeb 1, 2024 · The sum of the first n terms of an AP is given by Sn, = 3n^2 - 4n. Determine the AP and the 12th term. ← Prev Question Next Question → +3 votes 79.8k views asked Feb 1, 2024 in Mathematics by Kundan kumar (51.5k points) The sum of the first n terms of an AP is given by S n, = 3n 2 - 4n. Determine the AP and the 12 th term. arithmetic progression
WebMar 29, 2024 · Transcript. Ex 5.3, 3 In an AP (vi) Given a = 2, d = 8, Sn = 90, find n and an. Given a = 2, d = 8, Sn = 90 We can use formula Sn = 𝑛/2 (2𝑎+ (𝑛−1)𝑑) Putting a = 2, d = 8, Sn = 90 90 = 𝑛/2 (2 × 2+ (𝑛−1) × 8) 90 = 𝑛/2 (4+8𝑛−8) 90 × 2 =𝑛 (4+8𝑛−8) 180 = n (8n – 4) 180 = 8n2 – 4n –180 + 8n2 – 4n = 0 ...
WebFeb 5, 2024 · answered If the sum of n terms of an AP is given by Sn=n (4n+1),then find the nth term of the AP See answers Advertisement ideba2011 Answer:given below Step-by-step explanation: follow the steps..... Advertisement sunitasahuo4 Answer: I think it will be help you Advertisement Advertisement flying spaces ferienhausWebAug 31, 2015 · an = 4n +5. We can find terms 1 to 5 by substituting n respectively in the expression. an = 4n +5. So, a1 = 4 ⋅ (1) + 5 = 9. a2 = 4 ⋅ (2) + 5 = 13. a3 = 4 ⋅ (3) + 5 = 17. a4 = 4 ⋅ (4) + 5 = 21. a4 = 4 ⋅ (5) + 5 = 25. green moroccan lanternWebDefinition 1: A mathematical sequence in which the difference between two consecutive terms is always a constant and it is abbreviated as AP. Definition 2: An arithmetic sequence or progression is defined as a … greenmore road nuneatonWebIn an AP, if S n=n(4n+1), fill the AP is 5, 13, __, --- Medium Solution Verified by Toppr Correct option is A 21 S n=n(4n+1) ∴S 1=a=1(4+1)=5 and S 2=a 1+a 2=2(4×2+1)=18 ⇒a+a+d=18⇒2a+d=18 ⇒d=18−2a=18−10=8 Therefore the AP is a,a+d,a+2d,.... i.e. 5,13,21,... Was this answer helpful? 0 0 Similar questions In an AP if a=1, a n=20 and S n=399, then n … flyingspace hausWebJan 20, 2014 · In an A.P.,if Sn = n (4n+1) ,find the A.P. Share with your friends 2 Follow 4 Varun.Rawat, Meritnation Expert added an answer, on 21/1/14 We have, S n = 4n 2 + n put n = 1, we get S 1 = 4 (1) 2 + 1 = 4 + 1 = 5 So, First term, a 1 = 5 Put n = 2 , we get S 2 = 4 (2) 2 + 2 = 18 so, a 2 = S 2 - S 1 = 18 - 5 = 13 Put n = 3, we get S 3 = 4 (3) 2 + 3 = 39 flying space haus preiseWebGiven that sn = 4n^2 + 2n. ----- (1) Substitute n = 1 in (1), we get sn = 4(1)^2 + 2(1) = 4 + 2 = 6. So, Sum of the first term of AP is 6 i.e a = 6. Now, Substitute n = 2 in (1), we get sn = 4(2)^2 + 2(2) = 4 * 4 + 2 * 2 = 16 + 4 = 20. So, Sum of the first 2 terms = 20. Now, First-term + second term = 20 6 + a2 = 20 a2 = 20 - 6 a2 = 4. Hence in AP, flyingspacesWebApr 10, 2024 · The Indian Navy has released the official notification 1400 vacancies for the Indian Navy SSR Agniveer Exam 2024. The selection process includes a Computer Based Test, Written Exam & Physical Fitness Test (PFT), and last stage of Medical Examination. Candidates applying for the exam must check the Indian Navy SSR Agniveer Eligibility … flying spaces haus