Nettet23. jun. 2024 · The digit count helper function is completely unnecessary int superDigit (long long m) { if (m<10) { return m; }else { int s = 0; do { s += m % 10; m = m / 10; }while (m > 0); return superDigit (s); } } You can eliminate the recursion by yourself by putting the whole thing into a loop. Nettet13. mar. 2024 · Java program to Count the number of digits in a given integer Java Programming Java8 Object Oriented Programming Read a number from user. Create …
统计正整数中指定数字的个数 - 代码先锋网
Nettet19. mar. 2024 · int countdigit(long number,int digit) { int num,count= 0; number = number < 0 ? -number : number; while (number) { num = number % 10; /*should number, not num,*/ if (num == digit) count++; number/= 10; } return count; } 原因很简单,就是这句改成这样: num = number % 10; 相关推荐 【剑指offer】43、1~n 整数中 1 出现 的 次数 … Nettet函数接口定义: int CountDigit( int number, int digit ) ; 其中 number 是不超过长整型的整数, digit 为 [0, 9]区间内的整数。 函数 CountDigit 应返回 number 中 digit 出现的次数。 #include #include int CountDigit(int number, int digit) { int j = 0; for (;;) { if (digit== ( abs (number) % 10 )) { j++; } number = number / 10; if (number == 0) { … how i met your mother nanny
Program to count digits in an integer (4 Different Methods)
Nettet16. feb. 2024 · Find count of digits in a number that divide the number. Given a positive integer n. The task is to find count of digits of number which evenly divides the number … Nettet16. jul. 2024 · int countDigit (long long n) { return floor(log10(n) + 1); } bool isBrilliant (int n) { int flag = 0; bool isPrime [n + 1]; SieveOfEratosthenes (n, isPrime); for (int i = 2; i < n; i++) { int x = n / i; if (isPrime [i] && isPrime [x] and x * i == n) { if (countDigit (i) == countDigit (x)) return true; } } return false; } int main () { int n = 1711; Nettet26. feb. 2024 · 函数接口定义: int CountDigit( int number, int digit ) ; 复制代码 其中 number 是不超过长整型的整数, digit 为 [0, 9]区间内的整数。 函数 CountDigit 应返回 number 中 digit 出现的次数。 裁判测试程序样例: how i met your mother nonton